Aptitude

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📘 Height-and-Distance
📘 series
📘 Time and Distance
📘 Time and Work
📘 Train

101. In a flight of 600 km, an aircraft was slowed down due to bad weather. Its average speed for the trip was reduced by 200 km/hr and the time of flight increased by 30 minutes. The duration of the flight is:

[A]. 1 hour
[B]. 2 hours
[C]. 3 hours
[D]. 4 hours
✅ The correct answer is option A.
Let the duration of the flight be x hours.

Then,
600
–
600
= 200

x
x + (1/2)

600
–
1200
= 200

x
2x + 1

x(2x + 1) = 3
2×2 + x – 3 = 0
(2x + 3)(x – 1) = 0
x = 1 hr.      [neglecting the -ve value of x]

107. X and Y can do a piece of work in 20 days and 12 days respectively. X started the work alone and then after 4 days Y joined him till the completion of the work. How long did the work last?

[A]. 6 days
[B]. 10 days
[C]. 15 days
[D]. 20 days
✅ The correct answer is option B.
Work done by X in 4 days =

1
x 4

=
1
.

20
5

Remaining work =

1 –
1

=
4
.

5
5

(X + Y)’s 1 day’s work =

1
+
1

=
8
=
2
.

20
12
60
15

Now,
2
work is done by X and Y in 1 day.

15

So,
4
work will be done by X and Y in

15
x
4

= 6 days.

5
2
5

Hence, total time taken = (6 + 4) days = 10 days.

108. 4 men and 6 women can complete a work in 8 days, while 3 men and 7 women can complete it in 10 days. In how many days will 10 women complete it?

[A]. 35
[B]. 40
[C]. 45
[D]. 50
✅ The correct answer is option B.
Let 1 man’s 1 day’s work = x and 1 woman’s 1 day’s work = y.

Then, 4x + 6y =
1
and 3x + 7y =
1
.

8
10

Solving the two equations, we get: x =
11
, y =
1

400
400

1 woman’s 1 day’s work =
1
.

400

10 women’s 1 day’s work =

1
x 10

=
1
.

400
40

Hence, 10 women will complete the work in 40 days.