Speed =
72 x
5
m/sec
= 20 m/sec.
18
Time = 26 sec.
Let the length of the train be x metres.
Then,
x + 250
= 20
26
x + 250 = 520
x = 270.
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72 x
5
m/sec
= 20 m/sec.
18
Time = 26 sec.
Let the length of the train be x metres.
Then,
x + 250
= 20
26
x + 250 = 520
x = 270.
Then,
x
=
x + 20
10
14
14x = 10x + 200
4x = 200
x = 50 km.
Time taken to cover 9 km =
9
x 60
min
= 10 min.
54
Then, speed of the train =
150
x
=
3
x
kmph.
100
2
75
–
75
=
125
x
(3/2)x
10 x 60
75
–
50
=
5
x
x
24
x =
25 x24
= 120 kmph.
5
Then, 8x =
400
= 100
4
x =
100
= 12.5
8
Speed of first train = (7 x 12.5) km/hr = 87.5 km/hr.
21
24
x
+
x
= 20
21
24
15x = 168 x 20
x =
168 x 20
= 224 km.
15
Then,
x
–
x
= 2
10
15
3x – 2x = 60
x = 60 km.
Time taken to travel 60 km at 10 km/hr =
60
hrs
= 6 hrs.
10
So, Robert started 6 hours before 2 P.M. i.e., at 8 A.M.
Required speed =
60
kmph.
= 12 kmph.
5
Required speed =
1200 x
3
km/hr
= 720 km/hr.
5
Then,
120
+
480
= 8 Â Â Â
1
+
4
=
1
….(i)
x
y
x
y
15
And,
200
+
400
=
25
 Â
1
+
2
=
1
….(ii)
x
y
3
x
y
24
Solving (i) and (ii), we get: x = 60 and y = 80.
Ratio of speeds = 60 : 80 = 3 : 4.
160
+
160
hrs.
=
9
hrs.
64
80
2
Average speed =
320 x
2
km/hr
= 71.11 km/hr.
9