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101. In a flight of 600 km, an aircraft was slowed down due to bad weather. Its average speed for the trip was reduced by 200 km/hr and the time of flight increased by 30 minutes. The duration of the flight is:

[A]. 1 hour
[B]. 2 hours
[C]. 3 hours
[D]. 4 hours
✅ The correct answer is option A.
Let the duration of the flight be x hours.

Then,
600

600
= 200

x
x + (1/2)

600

1200
= 200

x
2x + 1

x(2x + 1) = 3
2×2 + x – 3 = 0
(2x + 3)(x – 1) = 0
x = 1 hr.      [neglecting the -ve value of x]

63. A train overtakes two persons who are walking in the same direction in which the train is going, at the rate of 2 kmph and 4 kmph and passes them completely in 9 and 10 seconds respectively. The length of the train is:

[A]. 45 m
[B]. 50 m
[C]. 54 m
[D]. 72 m
✅ The correct answer is option B.
2 kmph =

2 x
5

m/sec =
5
m/sec.

18
9

4 kmph =

4 x
5

m/sec =
10
m/sec.

18
9

Let the length of the train be x metres and its speed by y m/sec.

Then,

x

= 9 and

x

= 10.

y –
5

9

y –
10

9

9y – 5 = x and 10(9y – 10) = 9x
9y – x = 5 and 90y – 9x = 100.
On solving, we get: x = 50.
Length of the train is 50 m.

65. Two goods train each 500 m long, are running in opposite directions on parallel tracks. Their speeds are 45 km/hr and 30 km/hr respectively. Find the time taken by the slower train to pass the driver of the faster one.

[A]. 12 sec
[B]. 24 sec
[C]. 48 sec
[D]. 60 sec
✅ The correct answer is option B.
Relative speed =
= (45 + 30) km/hr

=

75 x
5

m/sec

18

=

125

m/sec.

6

We have to find the time taken by the slower train to pass the DRIVER of the faster train and not the complete train.

So, distance covered = Length of the slower train.

Therefore, Distance covered = 500 m.

Required time =

500 x
6

= 24 sec.

125

69. Two stations A and B are 110 km apart on a straight line. One train starts from A at 7 a.m. and travels towards B at 20 kmph. Another train starts from B at 8 a.m. and travels towards A at a speed of 25 kmph. At what time will they meet?

[A]. 9 a.m.
[B]. 10 a.m.
[C]. 10.30 a.m.
[D]. 11 a.m.
✅ The correct answer is option B.
Suppose they meet x hours after 7 a.m.
Distance covered by A in x hours = 20x km.
Distance covered by B in (x – 1) hours = 25(x – 1) km.
20x + 25(x – 1) = 110
45x = 135
x = 3.
So, they meet at 10 a.m.
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