67. A train moves past a telegraph post and a bridge 264 m long in 8 seconds and 20 seconds respectively. What is the speed of the train?

By /
[A]. 69.5 km/hr
[B]. 70 km/hr
[C]. 79 km/hr
[D]. 79.2 km/hr
✅ The correct answer is option D.
Let the length of the train be x metres and its speed by y m/sec.

Then,
x
= 8         x = 8y

y

Now,
x + 264
= y

20

8y + 264 = 20y
y = 22.

Speed = 22 m/sec =

22 x
18

km/hr = 79.2 km/hr.

5

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