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133. A and B together can do a piece of work in 30 days. A having worked for 16 days, B finishes the remaining work alone in 44 days. In how many days shall B finish the whole work alone?

[A]. 30 days
[B]. 40 days
[C]. 60 days
[D]. 70 days
✅ The correct answer is option C.
Let A’s 1 day’s work = x and B’s 1 day’s work = y.

Then, x + y =
1
and 16x + 44y = 1.

30

Solving these two equations, we get: x =
1
and y =
1

60
60

B’s 1 day’s work =
1
.

60

Hence, B alone shall finish the whole work in 60 days.

107. X and Y can do a piece of work in 20 days and 12 days respectively. X started the work alone and then after 4 days Y joined him till the completion of the work. How long did the work last?

[A]. 6 days
[B]. 10 days
[C]. 15 days
[D]. 20 days
✅ The correct answer is option B.
Work done by X in 4 days =

1
x 4

=
1
.

20
5

Remaining work =

1 –
1

=
4
.

5
5

(X + Y)’s 1 day’s work =

1
+
1

=
8
=
2
.

20
12
60
15

Now,
2
work is done by X and Y in 1 day.

15

So,
4
work will be done by X and Y in

15
x
4

= 6 days.

5
2
5

Hence, total time taken = (6 + 4) days = 10 days.

113. Ravi and Kumar are working on an assignment. Ravi takes 6 hours to type 32 pages on a computer, while Kumar takes 5 hours to type 40 pages. How much time will they take, working together on two different computers to type an assignment of 110 pages?

[A]. 7 hours 30 minutes
[B]. 8 hours
[C]. 8 hours 15 minutes
[D]. 8 hours 25 minutes
✅ The correct answer is option C.
Number of pages typed by Ravi in 1 hour =
32
=
16
.

6
3

Number of pages typed by Kumar in 1 hour =
40
= 8.

5

Number of pages typed by both in 1 hour =

16
+ 8

=
40
.

3
3

Time taken by both to type 110 pages =

110 x
3

hours

40

= 8
1
hours (or) 8 hours 15 minutes.

4

117. A and B can complete a work in 15 days and 10 days respectively. They started doing the work together but after 2 days B had to leave and A alone completed the remaining work. The whole work was completed in :

[A]. 8 days
[B]. 10 days
[C]. 12 days
[D]. 15 days
✅ The correct answer is option C.
(A + B)’s 1 day’s work =

1
+
1

=
1
.

15
10
6

Work done by A and B in 2 days =

1
x 2

=
1
.

6
3

Remaining work =

1 –
1

=
2
.

3
3

Now,
1
work is done by A in 1 day.

15

2
work will be done by a in

15 x
2

= 10 days.

3
3

Hence, the total time taken = (10 + 2) = 12 days.

119. If 6 men and 8 boys can do a piece of work in 10 days while 26 men and 48 boys can do the same in 2 days, the time taken by 15 men and 20 boys in doing the same type of work will be:

[A]. 4 days
[B]. 5 days
[C]. 6 days
[D]. 7 days
✅ The correct answer is option A.
Let 1 man’s 1 day’s work = x and 1 boy’s 1 day’s work = y.

Then, 6x + 8y =
1
and 26x + 48y =
1
.

10
2

Solving these two equations, we get : x =
1
and y =
1
.

100
200

(15 men + 20 boy)’s 1 day’s work =

15
+
20

=
1
.

100
200
4

15 men and 20 boys can do the work in 4 days.

121. A does 80% of a work in 20 days. He then calls in B and they together finish the remaining work in 3 days. How long B alone would take to do the whole work?

[A]. 23 days
[B]. 37 days
[C]. 37
[D]. 40 days
✅ The correct answer is option C.
Whole work is done by A in

20 x
5

= 25 days.

4

Now,

1 –
4

i.e.,
1
work is done by A and B in 3 days.

5
5

Whole work will be done by A and B in (3 x 5) = 15 days.

A’s 1 day’s work =
1
, (A + B)’s 1 day’s work =
1
.

25
15

B’s 1 day’s work =

1

1

=
4
=
2
.

15
25
150
75

So, B alone would do the work in
75
= 37
1
days.

2
2

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