Train

12. Two goods train each 500 m long, are running in opposite directions on parallel tracks. Their speeds are 45 km/hr and 30 km/hr respectively. Find the time taken by the slower train to pass the driver of the faster one.

[A]. 12 sec
[B]. 24 sec
[C]. 48 sec
[D]. 60 sec
✅ The correct answer is option B.
Relative speed =
= (45 + 30) km/hr

=

75 x
5

m/sec

18

=

125

m/sec.

6

We have to find the time taken by the slower train to pass the DRIVER of the faster train and not the complete train.

So, distance covered = Length of the slower train.

Therefore, Distance covered = 500 m.

Required time =

500 x
6

= 24 sec.

125

16. Two stations A and B are 110 km apart on a straight line. One train starts from A at 7 a.m. and travels towards B at 20 kmph. Another train starts from B at 8 a.m. and travels towards A at a speed of 25 kmph. At what time will they meet?

[A]. 9 a.m.
[B]. 10 a.m.
[C]. 10.30 a.m.
[D]. 11 a.m.
✅ The correct answer is option B.
Suppose they meet x hours after 7 a.m.
Distance covered by A in x hours = 20x km.
Distance covered by B in (x – 1) hours = 25(x – 1) km.
20x + 25(x – 1) = 110
45x = 135
x = 3.
So, they meet at 10 a.m.
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