11. A can finish a work in 24 days, B in 9 days and C in 12 days. B and C start the work but are forced to leave after 3 days. The remaining work was done by A in:
(B + C)’s 1 day’s work =
1
+
1
=
7
.
9
12
36
Work done by B and C in 3 days =
7
x 3
=
7
.
36
12
Remaining work =
1 –
7
=
5
.
12
12
Now,
1
work is done by A in 1 day.
24
So,
5
work is done by A in
24 x
5
= 10 days.
12
12