373. At 10 a.m. two trains started traveling toward each other from stations 287 miles apart. They passed each other at 1:30 p.m. the same day. If the average speed of the faster train exceeded the average speed of the slower train by 6 miles per hour, which of the following represents the speed of the faster train, in miles per hour?

By Admin / September 23, 2025

A. 38

B. 40

C. 44

D. 48

✅ The correct answer is option C. 44.
Let the speed of the faster train be x miles per hour and

the distance travelled by it when it meets the slower train be y miles. Time taken by the faster train to cover y miles

= Time taken by the slower train to cover (287-y) miles

= 3.5 hours (y/x) = (287-y)/(x-6) = 3.5 Solving, x = 44 miles/hr

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