A. 300 km
B. 290 km
C. 250 km
D. 240 km
✅ The correct answer is option B. 290 km.
Total distance = (120*2) + (100*(1/2)) = 290 km
Total distance = (120*2) + (100*(1/2)) = 290 km
Time & Distance Mcqs MCQs
A boy goes to his school from his house at a speed of 3 km / hr and returns at a speed of 2 km / hr. If he takes 5 hours in going and coming, the distance between his house and school is :___________?
A. 5 km
B. 5.5 km
C. 6 km
D. 6.5 km
✅ The correct answer is option C. 6 km.
Average speed = ( 2 X 3 X 2/3 + 2 ) km/ hr = 12/5 km/ hr. Distance travelled = ( 12/5 X 5 )km = 12 km. So Distance between house and school = ( 12/2 )km = 6 km.
Average speed = ( 2 X 3 X 2/3 + 2 ) km/ hr = 12/5 km/ hr. Distance travelled = ( 12/5 X 5 )km = 12 km. So Distance between house and school = ( 12/2 )km = 6 km.
A train when moves at an average speed of 40 kmph, reaches its destination on time. When its average speed becomes 35 kmph, then it reaches its destination 15 minutes late. Find the length of journey.
A. 30 km
B. 40 km
C. 70 km
D. 80 km
✅ The correct answer is option C. 70 km.
A person walking at 5/6th of his usual speed is 40 minutes late to his office. What is his usual travel time to his office?
A. 3 hours 20 minutes
B. 3 hours 15 minutes
C. 3 hours 30 minutes
D. 3 hours
✅ The correct answer is option A. 3 hours 20 minutes.
Let his usual speed be x kmph, the distance to his office be y km and his usual travel time be t hrs. y = xt = (5/6)x * (t+(40/60)) Solving the equation,
Let his usual speed be x kmph, the distance to his office be y km and his usual travel time be t hrs. y = xt = (5/6)x * (t+(40/60)) Solving the equation,
t = 3.33 hrs = 3 hrs 20 minutes
A car is running at a speed of 108 kmph. What distance will it cover in 15 seconds ?
A. 45 metres
B. 55 metres
C. 450 metres
D. Cannot be determined
✅ The correct answer is option C. 450 metres.
Barkat is travelling on his cycle and has calculated to reach point A at 2 P.M. if he travels at 10 kmph; he will reach there at 12 noon if he travels at 15 kmph. At what speed must he travel to reach A at 1 P.M. ?
A. 8 kmph
B. 11 kmph
C. 12 kmph
D. 14 kmph
✅ The correct answer is option C. 12 kmph.
There are 21 poles with a constant distance between each pole. A car takes 30 seconds to reach the 16th pole. How long does it take to reach the last pole?
A. 39 seconds
B. 40 seconds
C. 39.38 seconds
D. 39.5 seconds
✅ The correct answer is option B. 40 seconds.
The first pole is crossed at the zeroth second. The timer starts after the car crosses the first pole. Let the distance between each pole be x m. To reach the 16th pole, the distance travelled by the car is 15x. The speed of the car is 15x/30 = x/2 m/s To reach the 21st pole, it has to travel a distance of 20x. Time taken
The first pole is crossed at the zeroth second. The timer starts after the car crosses the first pole. Let the distance between each pole be x m. To reach the 16th pole, the distance travelled by the car is 15x. The speed of the car is 15x/30 = x/2 m/s To reach the 21st pole, it has to travel a distance of 20x. Time taken
= 20x÷(x/2)
= 40 seconds
A can complete a journey in 10 hours. He travels first half of the journey at the rate of 21 km / hr and second half at the rate of 24 km / hr. Find the total journey in km.
A. 220 km
B. 224 km
C. 230 km
D. 234 km
✅ The correct answer is option B. 224 km.
A walks around a circular field at the rate of one round per hour while B runs around it at the rate of six rounds per hour. They start in the same direction from the same point at 7.30 a.m. They shall first cross each other at :___________?
A. 7.42 a.m.
B. 7.48 a.m.
C. 8.10 a.m.
D. 8.30 a.m.
✅ The correct answer is option A. 7.42 a.m..
A and B go cycling in the same direction with speeds of 6 km/hr and 12 km/hr. A car from behind passes them in 9 and 10 seconds respectively. What is the speed of the car?
A. 22 km/hr
B. 33 km/hr
C. 66 km/hr
D. 44 km/hr
✅ The correct answer is option C. 66 km/hr.
The relative speed of A and B is 6 km/hr = 1.67 m/s
The relative speed of A and B is 6 km/hr = 1.67 m/s
As the car passes A after 10s, the distance between A and B after 10s (i.e. at 11th second) is the distance covered by car in 1 second.
Therefore, at t = 11, d = 1.67 * 11
d = 18.33 m
v = d/t = 18.33/1 = 18.33m/s
v = 66 km/hr