Mathematics
Practice the latest Mathematics MCQs with answers and explanations to excel in exams, interviews, and job tests. Our collection covers algebra, calculus, geometry, trigonometry, statistics, probability, arithmetic, matrices, and differential equations. These Mathematics multiple-choice questions are designed for students, competitive exam aspirants, and professionals preparing for NTS, PPSC, FPSC, CSS, PMS, university entry tests, and recruitment assessments. Strengthen your problem-solving skills, improve accuracy, and boost your exam performance with our updated Mathematics MCQs.
62. A walks around a circular field at the rate of one round per hour while B runs around it at the rate of six rounds per hour. They start in the same direction from the same point at 7.30 a.m. They shall first cross each other at :___________?
63. The average of 1st 3 of 4 numbers is 16 and of the last 3 are 15. If the sum of the first and the last number is 13. What is the last numbers?
A + B + C = 48
64. A man buys Rs. 20 shares paying 9% dividend. The man wants to have an interest of 12% on his money. The market value of each share is:_________?
Dividend on Rs. 20 = Rs. (90/100)x 20 = Rs.9/5.
Rs. 12 is an income on Rs. 100.
65. In an examination, every candidate took physics or mathematics or both 65.8% took physics and 59.2% took mathematics the total number of candidates was 2000. How many candidates took both physics and mathematics?
66. A and B go cycling in the same direction with speeds of 6 km/hr and 12 km/hr. A car from behind passes them in 9 and 10 seconds respectively. What is the speed of the car?
The relative speed of A and B is 6 km/hr = 1.67 m/s
As the car passes A after 10s, the distance between A and B after 10s (i.e. at 11th second) is the distance covered by car in 1 second.
Therefore, at t = 11, d = 1.67 * 11
d = 18.33 m
v = d/t = 18.33/1 = 18.33m/s
v = 66 km/hr
67. The ratio of the number of boys and girls in a college is 7 : 8. If the percentage iikcrease in the number of boys and girls be 20% and 10% respectively, what will be the new ratio ?
Originally, let the number of boys and girls in the college be 7x and 8x respectively. Their increased number is (120% of 7x) and (110% of 8x), i . e . ( 120/100 X 7x ) and ( 110/100 X 8x ) i . e . 42x/5 and 44x/5 Required ratio = 42x/5 : 44x/5 = 21 : 22
68. A sum was put a simple interest at a certain rate for 2 years. Had it been put at 4% higher rate, it would have fetched Rs. 60 more. The sum is:________?
69. The average of 9 observations was 9, that of the 1st of 5 being 10 and that of the last 5 being 8. What was the 5th observation?
1 to 9 = 9 * 9 = 81