7771. With decrease in temperature, the equilibrium conversion of a reversible endother- mic reaction
Decreases
Increases
Remains unaffected
Increases linearly with temperature
✅ The correct answer is option A.
Chemical Engineering
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7772. Transition state theory gives the rate constant as
K α e-E/RT
K α eE/RT
K α T . e-E/RT
K α √T . e-E/RT
✅ The correct answer is option C.
7773. The molecularity and the order of reaction respectively, for the hydrolysis of methyl acetate in presence of acids are
2 & 1
11 & 2
2 && 2
1 & 1
✅ The correct answer is option A.
7774. The knowledge of initial concentration and rate constant is necessary to determine the half life time of a reaction of __________ order.
Zero
First
Second
None of these
✅ The correct answer is option C.
7775. Effectiveness factor of a catalyst pellet is a measure of the __________ resistance.
Pore diffusion
Gas film
Chemical reaction
None of these
✅ The correct answer is option A.
7776. In which of the following gaseous phase reactions, the equilibrium of the reaction remains unaffacted by pressure changes ?
2O? ? 3O?
N? + O? ? 2NO
2NO? ? N?O?
2SO? + O? ? 2SO?
✅ The correct answer is option B.
7777. What is the unit of the rate constant in a chemical reaction in which 10% of the reactant decomposes in one hour, 20% in two hours, 30% in three hours and so on?
Litre/mole.second
Moles/litre.second
Litre/mole
Litre/second
✅ The correct answer is option A.
7778. Signal normally used to study non-ideal flow by stimulus response technique is __________ input.
Pulse
Step
Both A & B
Neither A nor B
✅ The correct answer is option C.
7779. A batch adiabatic reactor at an initial temperature of 373°K is being used for the reaction, A → B. Assume the heat of reaction is – 1kJ/mole at 373°K and heat capacity of both A and B to be constant and equal to 50J/mole.K. The temperature rise after a conversion of 0.5 will be
5°C
10°C
20°C
100°C
✅ The correct answer is option B.
7780. The rate expression for a heterogenous catalytic reaction is given by, – rA = K.KA PA(1 + KA.PA + Kr.PR), where K is surface reaction rate constant and KA and KR are absorption equilibrium constants of A and R respectively. If KR PR >> (1 + KA PA), the apparent activation energy EA is equal to (given E is the activation energy for the reaction and ΔHR and ΔHA are the activation energies of adsorption of R and A)
E
E + ΔHA
E + ΔHA – ΔHR
ΔHA + ΔHR
✅ The correct answer is option C.