Distance = (240 x 5) = 1200 km.
Speed = Distance/Time
Speed = 1200/(5/3) km/hr. [We can write 1 hours as 5/3 hours]
Required speed =
1200 x
3
km/hr
= 720 km/hr.
5
Required speed =
1200 x
3
km/hr
= 720 km/hr.
5
Then,
120
+
480
= 8
1
+
4
=
1
….(i)
x
y
x
y
15
And,
200
+
400
=
25
1
+
2
=
1
….(ii)
x
y
3
x
y
24
Solving (i) and (ii), we get: x = 60 and y = 80.
Ratio of speeds = 60 : 80 = 3 : 4.
160
+
160
hrs.
=
9
hrs.
64
80
2
Average speed =
320 x
2
km/hr
= 71.11 km/hr.
9
Then,
600
–
600
= 200
x
x + (1/2)
600
–
1200
= 200
x
2x + 1
x(2x + 1) = 3
2×2 + x – 3 = 0
(2x + 3)(x – 1) = 0
x = 1 hr. [neglecting the -ve value of x]
Then,
30
–
30
= 3
x
2x
6x = 30
x = 5 km/hr.