119. If 6 men and 8 boys can do a piece of work in 10 days while 26 men and 48 boys can do the same in 2 days, the time taken by 15 men and 20 boys in doing the same type of work will be:

✅ The correct answer is option A.
Let 1 man’s 1 day’s work = x and 1 boy’s 1 day’s work = y.

Then, 6x + 8y =
1
and 26x + 48y =
1
.

10
2

Solving these two equations, we get : x =
1
and y =
1
.

100
200

(15 men + 20 boy)’s 1 day’s work =

15
+
20

=
1
.

100
200
4

15 men and 20 boys can do the work in 4 days.