13706. According to parallel axis theorem, the moment of inertia of a section about an axis parallel to the axis through centre of gravity (i.e. IP) is given by(where, A = Area of the section, IG = Moment of inertia of the section about an axis passing through its C.G., and h = Distance between C.G. and the parallel axis.)

IP = IG + Ah2
IP = IG – Ah2
IP = IG / Ah2
IP = Ah2 / IG
✅ The correct answer is option A.

Leave a Comment

Your email address will not be published. Required fields are marked *

Scroll to Top